Sunday, December 14, 2008

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Thursday, December 4, 2008

Determination of pressure coefficient : Jolly’s bulb method.

Description:

Consider a bulb (A) kept in a container and is attached to a doubly bent glass tube. The other end of the tube is connected to a rubber tube, and the rubber tube is connected to a reservoir. The reservoir is attached to a retard stand and it is free to move on the retard stand. A vertical scale is fixed behind the rubber tube to measure the pressure.

Procedure:

Send dry air into the glass bulb several times and moisture should be removed from the glass bulb. Now the glass bulb is filled with dry air and the reservoir is partially filled with mercury. Ice cubes are kept in the container, so that the glass bulb attains 00c temperature and the gas is cooled. Now mark the mercury level on the rubber tube. The level difference in the two limbs can be measured by the vertical scale and is noted as h1. The atmospheric pressure H can be measured by Fortin’s Barometer.

The pressure at this temperature is noted as P0 = H ±h1.

Now the ice cubes are replaced with water and the water is boiled upto temperature T. Temperature can be measured by thermometer . After some time the bulb atains the temperature as the water and the volume of the gas increases. The mercury in the rubber tube moves down. But we have to find the pressure at this temperature at constant volume, for that we have to raise the reservoir till the mercury in the left limb reached point M. Now fix the reservoir and the level difference in the two limbs is measured by the vertical scale.

The pressure at this temperature is noted as Pt = H ±h2.

Pressure co-efficient of the gas can be measured by β = (Pt-P0)/(P0 t).

Result of the Experiment

Experimental result gives the Pressure coefficient of air as 0.003671/0C . or 1/ 273.16/0C.

Precautions:

Volume of the air must be constant throughout the experiment .
Before the experiment the apparatus must be cleaned with dry air properly.

All the best
Cheers
Giri Prasad. M

Regnault method to determine the Volume co-efficient of a gas

Description

A large bulb A of about 700 cc capacity is kept in a glass chamber and a capillary tube K with side tube E is attached to it. Other end of the capillary tube is connected to a manometer. The manometer is calibrated to find the pressure and it is kept in a glass container filled with water to maintain constant temperature.

Procedure:

The glass bulb is evacuated with a vacuum pump and several times hot air is sent into it to clean the moisture. The glass chamber is filled with ice cubes, after some time, the glass bulb attains 00c. The mercury level in the manometer adjusted such that the mercury level in the two limbs remains same. Now find the volume of gas in the bulb with the manometer calibration. Note it as V0.

Now the ice cubes in the manometer are replaced with water vapors. After some time the bulb attains 1000C., gas in the bulb attains the same temperature and expands, Due to this the mercury level in the left limb falls down and the mercury level in the right limb increases. At this stage, the mercury level is adjusted by the bottom tap. such that the levels in the two limbs are same. Now find the volume of the gas Vt.

Substitute the values in the formula

Result of the Experiment:

Regnault found the; volume coefficient of air as 0.003671/0C . or 1/ 273.16/0C.

Precautions:

1. The temperature in the container at the monometer must be maintained constant.

2. The two levels of the mercury must kept at the same level

Before the experiment the apparatus must be cleaned with dry air properly

Wednesday, December 3, 2008

Hi

Hi my dear readers!
This is Giri Prasad
Welcome you all to my new blog


Cheers

Giri...